Code:
js
/**
* @param {number[]} nums
* @return {number}
*/
var findMin = function(nums) {
let i = 0
let j = nums.length - 1
let min = nums[0]
while(i <= j) {
const m = Math.floor((i + j) / 2)
if (nums[m] >= nums[i]) {
min = Math.min(min, nums[i])
i = m + 1
} else {
min = Math.min(min, nums[m])
j = m - 1
}
}
return min
};
console.log(findMin([3,1,2]))